# Exercise And Solution On Application Of Double Integral Pdf

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## 14.2bE: Double Integrals Part 2 (Exercises)

To illustrate computing double integrals as iterated integrals , we start with the simplest example of a double integral over a rectangle and then move on to an integral over a triangle. For regions of other shapes, the range of one variable will depend on the other. In fact, the region is the triangle pictured below. Solution : A triangle is slightly more complicated than a rectangle because the limits of one variable will depend on the other variable. In a double integral, the outer limits must be constant, but the inner limits can depend on the outer variable.

## Math Insight

In Double Integrals over Rectangular Regions , we studied the concept of double integrals and examined the tools needed to compute them. We learned techniques and properties to integrate functions of two variables over rectangular regions. We also discussed several applications, such as finding the volume bounded above by a function over a rectangular region, finding area by integration, and calculating the average value of a function of two variables. In this section we consider double integrals of functions defined over a general bounded region D D on the plane. Most of the previous results hold in this situation as well, but some techniques need to be extended to cover this more general case. An example of a general bounded region D D on a plane is shown in Figure 5. In order to develop double integrals of f f over D , D , we extend the definition of the function to include all points on the rectangular region R R and then use the concepts and tools from the preceding section.

In this section we investigate double integrals and show how we can use them to find the volume of a solid over a rectangular region in the x y x y -plane. Many of the properties of double integrals are similar to those we have already discussed for single integrals. We begin by considering the space above a rectangular region R. The base of the solid is the rectangle R R in the x y x y -plane. We want to find the volume V V of the solid S. We do this by dividing the interval [ a , b ] [ a , b ] into m m subintervals and dividing the interval [ c , d ] [ c , d ] into n n subintervals.

This may be as a consequence either of the shape of the region, or of the complexity of the integrand. Calculating the double integral in the new coordinate system can be much simpler. We use change of variables to simplify the integral. Necessary cookies are absolutely essential for the website to function properly. This category only includes cookies that ensures basic functionalities and security features of the website. These cookies do not store any personal information.

## 14.2bE: Double Integrals Part 2 (Exercises)

If we have a mass density function for a lamina thin plate , how does a double integral determine the mass of the lamina? Given a mass density function on a lamina, how can we find the lamina's center of mass? What is a joint probability density function? How do we determine the probability of an event if we know a probability density function?

Recall that area between two curves is defined as the integral of the top curve minus the bottom curve. This idea can be brought to three dimensions. We defined the volume between two surfaces as the double integral of the top surface minus the bottom surface. This can be written formally with the theorem below. Then the volume of the surface is equal to the double integrals:.

Select the sample points to be the upper right corners of the subsquares of R. The depth of a 3-ft by 3-ft hole in the ground, measured at 1-ft intervals, is given in the following table. In the following exercises, calculate the integrals by interchanging the order of integration. In the following exercises, evaluate the iterated integrals by choosing the order of integration. In the following exercises, find the average value of the function over the given rectangles.

You might temporarily think of this surface as representing physical topography—a hilly landscape, perhaps. What is the average height of the surface or average altitude of the landscape over some region? As with most such problems, we start by thinking about how we might approximate the answer.

#### Chapter 4 : Multiple Integrals

The graphical interpretation of the double integral will be that it is the volume of the part of space under the roof. Most of the previous results hold in this situation as well, but some techniques need to be extended to cover this more general case. The most common multiple integrals are double and triple integrals, involving two or three variables, respectively. Calculate double integrals over a rectangle R. No enrollment or registration.

One difficult part of computing double integrals is determining the limits of integration, i. Changing the order of integration is slightly tricky because its hard to write down a specific algorithm for the procedure. We demonstrate this process with examples. The simplest region other than a rectangle for reversing the integration order is a triangle. You can see how to change the order of integration for a triangle by comparing example 2 with example 2' on the page of double integral examples.

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Да, Грег Хейл противный и наглый, но он же не предатель. Зная, чем грозит агентству Цифровая крепость, не мог же он участвовать в заговоре по ее созданию. И все же Сьюзан понимала, что остановить Хейла могут только его представления о чести и честности. Она вспомнила об алгоритме Попрыгунчик.

Интуиция подсказывала ей спасаться бегством, но у нее не было пароля от двери лифта. Сердце говорило ей, что она должна помочь Стратмору, но .

Беккер с трудом вел мотоцикл по крутым изломам улочки. Урчащий мотор шумным эхо отражался от стен, и он понимал, что это с головой выдает его в предутренней тишине квартала Санта-Крус. В данный момент у него только одно преимущество - скорость. Я должен поскорее выбраться отсюда.

К человеку в моем положении часто приходят с… ну, вы понимаете. - Да, мистер Клушар, конечно, понимаю. Это цена, которую приходится платить за известность.

Деление на ноль. Бринкерхофф высоко поднял брови. - Выходит, все в порядке. - Это лишь означает, - сказала она, пожимая плечами, - что сегодня мы не взломали ни одного шифра.

- Мидж снова оказалась права. - Идиот! - в сердцах воскликнула .

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Exercise 1. Express the following double integrals over a rectangle R as products of single integrals f(x, y) dxdy as an iterated double integral if D is a region bounded What is the Remark: Divide region in example (c) into two parts.